What are the divisors of 48?
Divisors of numbers
| Number | Prime factorization | Divisors |
|---|---|---|
| 47 | 47 | 1, 47 |
| 48 | 24 * 3 | 1, 2, 3, 4, 6, 8, 12, 16, 24, 48 |
| 49 | 72 | 1, 7, 49 |
| 50 | 52 * 2 | 1, 2, 5, 10, 25, 50 |
What are divisors of 91?
What is the list of divisors from 1 to 100?
| Number | List of Divisors |
|---|---|
| Divisors of 91 | 1,7,13,91 |
| Divisors of 92 | 1,2,4,23,46,92 |
| Divisors of 93 | 1,3,31,93 |
| Divisors of 94 | 1,2,47,94 |
How do you know how many divisors a number has?
In general, if you have the prime factorization of the number n, then to calculate how many divisors it has, you take all the exponents in the factorization, add 1 to each, and then multiply these “exponents + 1″s together.
What is the factors for 48?
Prime factorization is an extension of factorization in which all the factors are prime numbers. For example, suppose we want the prime factorization of 48 . The factors of 48 are 1, 2, 3, 4, 6, 8, 12, 16, 24, 48 .
What are the multiples of 48?
Solution: The first ten multiples of 48 are, 48, 96, 144, 192, 240, 288, 336, 384, 432 and 480.
What is the sum of all divisors of 91?
The number 91 can be divided by 4 positive divisors (out of which 0 are even, and 4 are odd). The sum of these divisors (counting 91) is 112, the average is 28.
How do you find the divisors of a number in Python?
Finding divisors of a number with Python
- def get_divisors(n): for i in range(1, int(n / 2) + 1): if n % i == 0: yield i yield n.
- def prime_factors(n): i = 2 while i * i <= n: if n % i == 0: n /= i yield i else: i += 1 if n > 1: yield n.
How do you find the divisors of 12?
So, the divisors or factors of the number 12 are 1,2,3,4,6 and 12.
How do you make 48?
The factor pairs of the number 48 are: 1 x 48, 2 x 24, 3 x 16, 4 x 12, and 6 x 8. When you multiply each of these factor pairs together, you get 48….